数论模板

Gavin

exgcd 求解逆元

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// ax%b==1
exgcd(a,b,x,y);
ans = (x+b)%b;

Miller-Rabin 素性测试 & Pollard-Rho

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#include <random>

const int TEST_TIME=16;
random_device rd;
mt19937_64 gen(rd());

ll bmul(ll a,ll b,ll m){
ull c=(ull)a*(ull)b-(ull)((ld)a/m*b+0.5L)*(ull)m;
if(c<(ull)m){
return c;
}
return c+m;
}

ll qpow(ll a,ll b,ll P){
ll res=1;
while(b>0){
if(b&1){
res = bmul(res,a,P);
}
a = bmul(a,a,P);
b >>= 1;
}
return res;
}

bool MillerRabin(ll n){
if(n<2){
return false;
}
if(n==2||n==3){
return true;
}

ll u=n-1,t=0;
while(u%2==0){
u /= 2;
t++;
}

uniform_int_distribution<ll> dist(0,n-4);

for(int i=1;i<=TEST_TIME;i++){
ll a=dist(gen)+2,v=qpow(a,u,n),s=0;
if(v==1){
continue;
}
for(s=0;s<t;s++){
if(v==n-1){
break;
}
v = bmul(v,v,n);
}
if(s==t){
return false;
}
}

return true;
}

ll gcd(ll a,ll b){
return b==0?a:gcd(b,a%b);
}

ll PollardRho(ll x){
ll s=0,t=0,c=uniform_int_distribution<>(0,x-2)(gen)+1,val=1;

for(int gl=1;;gl*=2,s=t,val=1){
for(int stp=1;stp<=gl;stp++){
t = (bmul(t,t,x)+c)%x;
val = bmul(val,abs(t-s),x);
if((stp%127)==0){
ll d=gcd(val,x);
if(d>1){
return d;
}
}
}
ll d=gcd(val,x);
if(d>1){
return d;
}
}
}

ll mxfac;
void maxFac(ll x,bool fst=true){
if(fst){
mxfac = 0;
}

if(x<=mxfac||x<2){
return;
}

if(MillerRabin(x)){
mxfac = max(mxfac,x);
return;
}

ll p=x;
while(p>=x){
p = PollardRho(x);
}
while((x%p)==0){
x /= p;
}

maxFac(x,false);
maxFac(p,false);
}

#include <vector>

vector<ll> facs;
void getFacs(ll x,bool fst=true){
if(fst){
facs.clear();
}

if(x==1){
return;
}

if(MillerRabin(x)){
facs.push_back(x);
return;
}

ll p=x;
while(p>=x){
p = PollardRho(x);
}
while((x%p)==0){
x /= p;
}

getFacs(x,false);
getFacs(p,false);
}

CRT

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void exgcd(ll a,ll b,ll &x,ll &y){
if(b==0){
x = 1;
y = 0;
}
else{
exgcd(b,a%b,y,x);
y -= a/b*x;
}
}

ll crt(int k,ll* a,ll* r){
ll n=1,ans=0;
for(int i=1;i<=k;i++){
n = n*a[i];
}
for(int i=1;i<=k;i++){
ll m=n/a[i],b,y;
exgcd(m,a[i],b,y);
ans = (ans+r[i]*m*b%n)%n;
}
return (ans%n+n)%n;
}

Lagrange Interpolation

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#include <vector>

ll qpow(ll a,ll b,ll P){
ll res=1;
while(b>0){
if(b&1){
res = res*a%P;
}
a = a*a%P;
b >>= 1;
}
return res;
}

ll inv(ll a,ll P){
return qpow(a,P-2,P);
}

vector<int> lagrangeInterpolation(const vector<int> &x,
const vector<int> &y,
ull P){
int n=x.size();
vector<int> M(n+1),px(n,1),f(n);
M[0] = 1;

for(int i=0;i<n;i++){
for(int j=i;j>=0;j--){
M[j+1] = (M[j]+M[j+1])%P;
M[j] = (ll)M[j]*(P-x[i])%P;
}
}

for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
if(i!=j){
px[i] = (ll)px[i]*(x[i]-x[j]+P)%P;
}
}
}

for(int i=0;i<n;i++){
ll t=(ll)y[i]*inv(px[i],P)%P,k=M[n];
for(int j=n-1;j>=0;j--){
f[j] = (f[j]+k*t)%P;
k = (M[j]+k*x[i])%P;
}
}

return f;
}

Lucas

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ll qpow(ll a,ll b,ll P){
ll res=1;
while(b>0){
if(b&1){
res = res*a%P;
}
a = a*a%P;
b >>= 1;
}
return res;
}

ll inv(ll a,ll P){
return qpow(a,P-2,P);
}

ll fac[100005],ifac[100005];

void init(int P){
fac[0] = 1;
for(int i=1;i<P;i++){
fac[i] = fac[i-1]*i%P;
}
ifac[P-1] = inv(fac[P-1],P);
for(int i=P-1;i>=1;i--){
ifac[i-1] = ifac[i]*i%P;
}
}

ll C(int n,int m,int P){
if(n<m){
return 0;
}
if(n<P&&m<P){
return fac[n]*ifac[n-m]%P*ifac[m]%P;
}
return C(n/P,m/P,P)*C(n%P,m%P,P)%P;
}

// -------------------------------------------

class BinomModPrime{
int p;
vector<int> fac,ifac;

int calc(int n,int k){
if(n<k){
return 0;
}
ll res=fac[n];
res = (res*ifac[k])%p;
res = (res*ifac[n-k])%p;
return res;
}

public:
BinomModPrime(int p):p(p),fac(p),ifac(p){
fac[0] = 1;
for(int i=1;i<p;i++){
fac[i] = (ll)fac[i-1]*i%p;
}
ifac[p-1] = p-1;
for(int i=p-1;i>=1;i--){
ifac[i-1] = (ll)ifac[i]*i%p;
}
}

int binomial(ll n,ll k){
ll res=1;
while(n>0||k>0){
res = (res*calc(n%p,k%p))%p;
n /= p;
k /= p;
}
return res;
}

int operator()(const ll &n,const ll &k){
return binomial(n,k);
}
};
  • 标题: 数论模板
  • 作者: Gavin
  • 创建于 : 2026-03-11 08:41:00
  • 更新于 : 2026-03-11 08:41:00
  • 链接: https://gavin-blog.pages.dev/2026/数论模板/
  • 版权声明: 本文章采用 CC BY-NC-SA 4.0 进行许可。